By E. Z.
\(\ F_ {net}=m\vec{u}''(t)=\vec{F}_{gravitational}+\vec{F}_{restoring}+\vec{F}_{damping}+\vec{F}_{external}\)
\(\ mu''+bu'+ku=f(t) \)
\(\ u(0)=u_0 \)\(\ u'(0)=u_1 \)
Given one solution \(\ y_1 \) to the homogenous equation: \(\ y''+p(x)y'+q(x)y=0 \), there is needed to be find \(\ y_2 \) such is linearly independent from \(\ y_1 \).
\(\ y_2=u(x)y_1(x), W(y_1, y_2 ) ≠ 0 \)
Let us apply the transformation:
independent variable to
dependent variable to
Then the DE becomes: \(\ u'' y_1 + u' (2y'_1 + p(x) y_1)=0 \)
By setting the DE becomes:
\(\ w' + [\frac{2y'}{y}+p(x)]=0 \)
which is a first order linear ODE & easy to solve.
After finding we can transform it back to .
If it is not possibe to find fundamental solutions for , using power series approximation to the position \(\ \small x_0 \):
\[\ \lim_{m \to ∞}( \sum_{n=0}^{m} a_n (x-x_0)^n ), x ∈ 𝕀 \]
Note: This theorem is not one of the achivements of this course but it is important to know to apply the method.
\[\ A(x)y''+B(x)y'+C(x)y=0 \]
Note: As far as this cource concerns we will only be solving series solutions for ordinary points.
Suppose \[\ y(x)= \sum_{k=0}^{∞}c_k(x-x_0)^k \] By supposing it satisfies the necessary conditions: \[\ y'(x)= \sum_{k=0}^{∞}c_kk(x-x_0)^{k-1} \text{ and } y''(x)= \sum_{k=0}^{∞}c_kk(k-1)(x-x_0)^{k-2} \] By substituting these formulas in place at DE, we can find \(\ c_k \)